Asked by mj jad
The given equation is a partial answer to a calculus problem. Solve the equation for the symbol y'.
6y2y' − y − xy' = x
y' =
6y2y' − y − xy' = x
y' =
Answers
Answered by
Reiny
y' is a common factor
y' (6y^2 - x) = x+y
y' = (x+y)/(6y^2 - x)
y' (6y^2 - x) = x+y
y' = (x+y)/(6y^2 - x)
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