Asked by jack
A wheel has a rotational velocity of 18·rad/s counterclockwise. You place you hand against the wheel and the friction between your hand and the rim stops it.
(a) If it takes 4·s to stop the wheel, what is its rotational acceleration?
rad/s2
(b) How far does the wheel rotate while slowing to a stop?
rad
(a) If it takes 4·s to stop the wheel, what is its rotational acceleration?
rad/s2
(b) How far does the wheel rotate while slowing to a stop?
rad
Answers
Answered by
jaykim
w=ar*t 18=4ar ar=4.5rad/s^2 (b)18^2=2ar*theta theta=36rad
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.