A wheel has a rotational velocity of 18·rad/s counterclockwise. You place you hand against the wheel and the friction between your hand and the rim stops it.
(a) If it takes 4·s to stop the wheel, what is its rotational acceleration?
rad/s2
(b) How far does the wheel rotate while slowing to a stop?
rad
1 answer
w=ar*t 18=4ar ar=4.5rad/s^2 (b)18^2=2ar*theta theta=36rad
1 answer