Asked by Anonymous
The rotational velocity of a merry-go-round increases at a constant rate from 1 rad/s to 2.1 rad/s in a time of 5.8 s. What is the rotational acceleration of the merry-go-round?
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Answered by
Anonymous
a= change in w divided by change in t
(Wfinal- Winitial)/ time
(2.1-1)/5.8
=0.189655172 rad/s ^2
(Wfinal- Winitial)/ time
(2.1-1)/5.8
=0.189655172 rad/s ^2
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