Asked by Brittney
An original samplemof an unknown potassium chloride/potassium cholate mixture weighed 1.042g before heating and 0.943g after heating. How many grams of oxygen were released?
Answers
Answered by
DrBob222
2KClO3 ==> 2KCl + 3O2
Loss in mass = mass O2 lost = 1.042-0.943 = 0.099
mols O2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols O2 to mols KClO3.
Then convert mols KClO3 to grams KClO3 with g = mols x molar mass.
Loss in mass = mass O2 lost = 1.042-0.943 = 0.099
mols O2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols O2 to mols KClO3.
Then convert mols KClO3 to grams KClO3 with g = mols x molar mass.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.