Asked by Hannah
Exactly 5.02 grams of an unknown gas was sealed in a 3.0L flask at 37 degrees celsius and a pressure of 1.25 atm. Which on of the following is most likely to be the unknown?
H2O, HBr, HCN, H2S, C2H2
ok so I did (1.25)(3.0) = n(0.0821)(310)
3.75 = n(25.451)
n=0.1473
Then I did 0.1473= 5.02/mm and I got 34.08 and this is the mm for H2S. Is this correct?
H2O, HBr, HCN, H2S, C2H2
ok so I did (1.25)(3.0) = n(0.0821)(310)
3.75 = n(25.451)
n=0.1473
Then I did 0.1473= 5.02/mm and I got 34.08 and this is the mm for H2S. Is this correct?
Answers
Answered by
DrBob222
That looks ok to me.
H2O is about 18
HBr = about 80 or so
HCN is about 27
H2S is about 34
C2H2 is about 26.
H2O is about 18
HBr = about 80 or so
HCN is about 27
H2S is about 34
C2H2 is about 26.
Answered by
Hannah
Ok thank you
Answered by
ChemStudent
that is correct. The MM for Hs@ is 34.1. Closes to 5.02/0.147=34.15.
Answered by
Alex
You can also use d=PM/RT. Density is mass/volume. Plug it in and solve for M.
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