V-Vo = 6.24/m/s[-54.3o]-5.45m/s[38.5o]
X = 6.24*Cos(-54.3) - 5.45*Cos38.5 = -0.624 m/s
Y = 6.24*sin(-54.3) - 5.45*sin38.5 = -8.46 m/s
ax = -0.624/4.0 = -0.156 m/s^2
ay = -8.46/4.0 = -2.115 m/s^2
Initially, a particle is moving at 5.45 m/s at an angle of 38.5° above the horizontal. Four seconds later, its velocity is 6.24 m/s at an angle of 54.3° below the horizontal. What was the particle's average acceleration during these 4.00 seconds in the x-direction (enter first) and the y-direction?
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1 answer