Asked by Kayla
At time t=0, in seconds, a pair of sunglasses is dropped from the Eiffel Tower in Paris. At time t, its height in feet above the ground is given by h(t)=−16t^2+1000.
When do the sunglasses hit the ground? Include units in your answer.
I got that the height is 1000ft and I have tried factoring it but I am not sure where to go now. I can't figure out how to set it up.
When do the sunglasses hit the ground? Include units in your answer.
I got that the height is 1000ft and I have tried factoring it but I am not sure where to go now. I can't figure out how to set it up.
Answers
Answered by
Steve
when it hits the ground, the height is zero. So, just solve
-16t^2 + 1000 = 0
16(62.5-t^2) = 0
t = √62.5 = 7.9
-16t^2 + 1000 = 0
16(62.5-t^2) = 0
t = √62.5 = 7.9
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