Asked by tsholofelo
When x^3+mx^2-5x+4 is divided by x+2,the remainder is 8.determine the value of m
Answers
Answered by
Steve
Use a little synthetic division to find that the remainder is 4m+6
So, m = 1/2
x^3 + (1/2)x^2-5x+4 = (x+2)(x^2-(3/2)x-2)+8
So, m = 1/2
x^3 + (1/2)x^2-5x+4 = (x+2)(x^2-(3/2)x-2)+8
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