H2C2O4 + 2NaOH ==> Na2C2O4 + 2H2O
mols H2C2O4 = M x L = ?
mols NaOH = 2x mols H2C2O4 (look at the coefficients)
M NaOH = mols NaOH/L NaOH
You know M and mols, solve for L NaoH.
In an acid-base titration, 33.12ml of 0.1177 M H2C2O4 was titrated with 0.2146 M NaOH to the end point. What volume of the NaOH solution was used?
1 answer
1 answer