Asked by Rose
In an acid base titration 32.5 mL of sodium hydroxide, NaOH, were neutralized by 17.6 mL of 0.180 mol/L sulfuric acid, H2SO4. Calculate the concentration of the sodium hydroxide.
Answers
Answered by
DrBob222
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols H2SO4 = M x L = ?
mols NaOH = twice that of H2SO4.[Note the coefficients in the balanced equation.]
M NaOH = mols NaOH/L NaOH
mols H2SO4 = M x L = ?
mols NaOH = twice that of H2SO4.[Note the coefficients in the balanced equation.]
M NaOH = mols NaOH/L NaOH
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