Particles of charge +65, +48, and −95 μC are placed in a line. The center one is L = 60cm from each of the others.Calculate the net force on the left charge due to the other two.

Answer 1

F = k Q1 Q2 /d^2
due to right one, +force because opposite sign
due to middle one, -force because of same sign
F = k(10^-6)(10^-6)(65) [ 95/1.2^2 -48/.6^2 ]

Answer 2

-46.9