Question

A bullet is fired through a wooden board with a thickness of 12.0 cm. The bullet hits the board perpendicular to it, and with a speed of +370 m/s. The bullet then emerges on the other side of the board with a speed of +333 m/s. Assuming constant acceleration (rather, deceleration!) of the bullet while inside the wooden board, calculate the acceleration

Answer 1

V^2 = Vo^2 + 2a*d
V = 333 m/s.
Vo = 370 m/s.
d = 12 cm = 0.12 m.
Solve for a. It will be negative.

Answer 2

-108379