Asked by danny



What is the specific heat capacity of aluminum if a 8.4 g sample increased 21.1 C upon the addition of 159.0 J? The units are J/(g ·K).
q=cpxMxT is the equation
my answer i got is 401.65 is that right bec i feel that's wrong
Answered by DrBob222
How in the world did you arrive at 401.65?
159.0J = 8.4g x sp.h. x 21.1
Solve for sp.h. = [159.0/(8.4*21.1)]
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