Asked by Seth
1) An equation of the line contains points (7/9, 7) and (-7/9) is
2) Find the slope of the line tangent to the curve y=x^2 at the point (-0.6, 0.36) and find the corresponding equation of the tangent line
2) Find the slope of the line tangent to the curve y=x^2 at the point (-0.6, 0.36) and find the corresponding equation of the tangent line
Answers
Answered by
Steve
#1 I only see one point and a number.
#2 at the given point, the slope is -1.2
So, the line there is
y-0.36 = -1.2(x+0.6)
#2 at the given point, the slope is -1.2
So, the line there is
y-0.36 = -1.2(x+0.6)