Al2(SO3)3 + 6NaOH ----> 3Na2SO3 = 2 Al9OH)3

Question

If 10.0g of Al2(SO3)3 is reacted with 10.0g of NaOH, determine the limiting reagent?
help!!!

Answer 1

I do these the long way.
Moles Al2*SO4)3 = grams/molar mass = ?
mols NaOH = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols Al2(SO3)3 to mols Na2SO3.
Do the same for mols NaOH to mols Na2SO3.
I think the answers will not be the same which means one is wrong; the correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.