Asked by david
A rod with length L and mass m stand on a frictionless table. a ball with mass m and speed u cimped perpendicular to the rod a distance x from the bottom of the rod and sticks to it. what is the angular velocity of the rod+ball after the collison?
I need help on how to solve it. i assumed that angular momentum is conserved but i know i reach a wrong solution please help....
I need help on how to solve it. i assumed that angular momentum is conserved but i know i reach a wrong solution please help....
Answers
Answered by
Damon
both angular and linear momentum are conserved. The center of gravity of the system is height:
h (m+m) = m x + m (L/2)
and it is moving at speed
Ucg (m+m) = u m
then of course you have the rotation about the cg
h (m+m) = m x + m (L/2)
and it is moving at speed
Ucg (m+m) = u m
then of course you have the rotation about the cg
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