Asked by rakesh
33. A rope of mass M and length L is being rotated about one end in a gravity free space. A pulse is being created at one of the ends. The angle through which rope will be rotated in the time when pulse reaches the opposite end of rope for first time and for the angular velocity of rope 'ω', is
a) π/√2 b) π/2 c) π/(2√2) d) π2
a) π/√2 b) π/2 c) π/(2√2) d) π2
Answers
Answered by
Damon
Tricky
pulse speed increases as you toward center
at every r, acceleration, a, which is like a variable g for us
a = omega^2 r
This is like the plse on a hanging rope problem
see:
http://www.usna.edu/Users/physics/mungan/_files/documents/Scholarship/HangingPulse.pdf
pulse speed increases as you toward center
at every r, acceleration, a, which is like a variable g for us
a = omega^2 r
This is like the plse on a hanging rope problem
see:
http://www.usna.edu/Users/physics/mungan/_files/documents/Scholarship/HangingPulse.pdf
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