Asked by zel
in a oblique triangle ABC ,it is known that tan A=3/4,cos B=5/13 an AB=10cm
find sinC,side AC, and side BC
find sinC,side AC, and side BC
Answers
Answered by
Steve
we know that A+B+C=180°, and we see that
A = 36.86°
B = 67.38°
So, C=75.76°
Now you can use the law of sines to find the other two sides.
A = 36.86°
B = 67.38°
So, C=75.76°
Now you can use the law of sines to find the other two sides.
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