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Asked by zel

in a oblique triangle ABC ,it is known that tan A=3/4,cos B=5/13 an AB=10cm
find sinC,side AC, and side BC
10 years ago

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Answered by Steve
we know that A+B+C=180°, and we see that
A = 36.86°
B = 67.38°
So, C=75.76°

Now you can use the law of sines to find the other two sides.
10 years ago
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