how do you find the oblique asymptote?
ex. q(x) = x^5/ (x^3 - 125)
4 answers
I think I remember that to get oblique or slant asymptotes, the numerator has to be one degree larger than the denominator, and in this, it is two degrees.
so if the numerator is one degree higher than how would you find the oblique asymptote?
such as
q(x) = (x^2 + x - 9)/(2 x - 4)
such as
q(x) = (x^2 + x - 9)/(2 x - 4)
divide the numberator by the denominator. You will get a first degree equation + remainder. The first degree equation is the slant asymtote.
http://www.purplemath.com/modules/asymtote3.htm
http://www.purplemath.com/modules/asymtote3.htm
okay thank you.