Asked by jasmine
how do you find the oblique asymptote?
ex. q(x) = x^5/ (x^3 - 125)
ex. q(x) = x^5/ (x^3 - 125)
Answers
Answered by
bobpursley
I think I remember that to get oblique or slant asymptotes, the numerator has to be one degree larger than the denominator, and in this, it is two degrees.
Answered by
jasmine
so if the numerator is one degree higher than how would you find the oblique asymptote?
such as
q(x) = (x^2 + x - 9)/(2 x - 4)
such as
q(x) = (x^2 + x - 9)/(2 x - 4)
Answered by
bobpursley
divide the numberator by the denominator. You will get a first degree equation + remainder. The first degree equation is the slant asymtote.
http://www.purplemath.com/modules/asymtote3.htm
http://www.purplemath.com/modules/asymtote3.htm
Answered by
jasmine
okay thank you.
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