Asked by Tee
THE POINT (8,-3)LIES ON THE CURVE Y=3/(7-X) (a)IF Q IS THE POINT (x,3/(7-X)) USE YOUR CALCULATOR TO FIND THE SLOPE OF THE SECANT LINE PQ CORRECT TO SIX DECIMAL PLACES FOR THE VALUE OF X.
(i)7.9 Mpq?
(ii)7.99 mPQ?
(iii)7.999Mpq?
(iV)7.9999 MPQ?
(i)7.9 Mpq?
(ii)7.99 mPQ?
(iii)7.999Mpq?
(iV)7.9999 MPQ?
Answers
Answered by
Steve
P = (8,-3)
The slope of PQ is
∆y/∆x = (3/(7-x)-(-3))/(x-8)
= (3+3(7-x))/((7-x)(x-8))
= (24-3x)/((7-x)(x-8))
You have provided no data about Q or the desired slope, but just plug in the numbers you have.
The slope of PQ is
∆y/∆x = (3/(7-x)-(-3))/(x-8)
= (3+3(7-x))/((7-x)(x-8))
= (24-3x)/((7-x)(x-8))
You have provided no data about Q or the desired slope, but just plug in the numbers you have.
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