Question

What is the pH of the resulting solution when 25.0mL of 0.100 HNO3(aq)are reacted with 20.0 mL of 0.175M NaOH(aq)? Is the resulting solution acidic or basic in nature?

Answer 1

HNO3 + NaOH ==> NaNO3 + H2O

mols HNO3 = M x L = approx 0.0025
mols NaOH = M x L = approx 0.0035
excess NaOH available is approx 0.001mols
M NaOH = mols/L = 0.001/0.045 = approx 0.02M
You need to redo all of these calculations since I've estimated.
Then poH = -log(OH^-)
Calculate pOH and substitute into the equation below.
pH + pOH = pKw = 14
You know pKw and pOH, solve for pH.
Is the solution acidic or basic?
pH<7 = acidic
pH=7 - neutral
pH>7 = basic

Answer 2

That was super helpful, thanks!