Asked by Devki
Hello, I am new to this website. I havea summer assignment on Algebra II. I need help on these problems. I find I be not able to understand them.
Simplify:
1)(mn^2/3)(4/mn)
2)(x+4/x-4)(1/x+4)
3)(x^2-16/2x+8)(x+4/x^2+8x+16)
4)(n/4)(n/m)
5)(3a^3-27a/2a^2+13a-7)(9a^2/4a^2-1)
Simplify:
1)(mn^2/3)(4/mn)
2)(x+4/x-4)(1/x+4)
3)(x^2-16/2x+8)(x+4/x^2+8x+16)
4)(n/4)(n/m)
5)(3a^3-27a/2a^2+13a-7)(9a^2/4a^2-1)
Answers
Answered by
Damon
Well, I will do one of them, then you try the rest and post your work. One of us will try to help if we see where you are running into trouble.
3)(x^2-16/2x+8)(x+4/x^2+8x+16)
[(x-4)(x+4) / 2(x+4 )][(x+4)/[(x+4)(x+4]]
[(x-4)/2)][1/(x+4)]
(x-4)/(2x+8)
3)(x^2-16/2x+8)(x+4/x^2+8x+16)
[(x-4)(x+4) / 2(x+4 )][(x+4)/[(x+4)(x+4]]
[(x-4)/2)][1/(x+4)]
(x-4)/(2x+8)
Answered by
Devki
Thank you!
Is this right?
(mn^2/3)(4/mn)
[(mn)(mn)/3] * [4/mn]
(mn/3)(4)
ANSWER: 4mn/3
Is this right?
(mn^2/3)(4/mn)
[(mn)(mn)/3] * [4/mn]
(mn/3)(4)
ANSWER: 4mn/3
Answered by
Damon
I do not think m is supposed to be squared the way you typed it, only n
(m n n /3) (4 / m n)
4 n / 3
(m n n /3) (4 / m n)
4 n / 3
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