Asked by slim stud
I know i'm a slow bunny and the answer is in my face but please help!
(4p-1)(16p^2+4p+1)
(4p-1)(16p^2+4p+1)
Answers
Answered by
drwls
Multiply (16p^2+4p+1) by 4p, and then subtract (16p^2+4p+1) from what you get.
64p^3 + 16 p^2 + 4p - 16p^2 -4p -1
= 64 p^3 -1.
64p^3 + 16 p^2 + 4p - 16p^2 -4p -1
= 64 p^3 -1.
Answered by
Anonymous
sorry man I still don get it. I have to find the product. I don't know where you got the 64^3 from. Can you please take me step by step
Answered by
drwls
There was no 64^3 in my anser.
64p^3 is the product of the 16 p^2 and 4p terms. I suggest you review the distributive propery of algebra:
a (b +c) = ab + ac
64p^3 is the product of the 16 p^2 and 4p terms. I suggest you review the distributive propery of algebra:
a (b +c) = ab + ac
Answered by
slimstud
ok thanks
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