Question

A ball is thrown straight up and reaches a maximum height of 6.57 m .
What was its initial speed? The accelera-
tion of gravity is 9.8 m/s2 . Answer in units of m/s

Answer 1

V^2 = Vo^2 + 2g*h

V = 0
g = -9.8 m/s^2
h = 6.57 m.
Solve for Vo.