Asked by jack
A ball is thrown straight up and reaches a maximum height of 6.57 m .
What was its initial speed? The accelera-
tion of gravity is 9.8 m/s2 . Answer in units of m/s
What was its initial speed? The accelera-
tion of gravity is 9.8 m/s2 . Answer in units of m/s
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h
V = 0
g = -9.8 m/s^2
h = 6.57 m.
Solve for Vo.
V = 0
g = -9.8 m/s^2
h = 6.57 m.
Solve for Vo.
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