Question

A tension force of 2.50 N acts horizontally on a 2.00 kg block. The block accelerates at 0.750 m/s2. What is the force of kinetic friction?

2 x .75, = 1.5N
(2.5 - 1.5) = 1N?????

Answer 1

Fnet=Ft-Ff

m*a=Ft-Ff

2.00kg*0.750=2.50N-Ff

1.5N=2.50N-Ff

1.5N/2.50N=Ff

Ff=0.6N