Asked by Jake
A tension force of 2.50 N acts horizontally on a 2.00 kg block. The block accelerates at 0.750 m/s2. What is the force of kinetic friction?
2 x .75, = 1.5N
(2.5 - 1.5) = 1N?????
2 x .75, = 1.5N
(2.5 - 1.5) = 1N?????
Answers
Answered by
Devron
Fnet=Ft-Ff
m*a=Ft-Ff
2.00kg*0.750=2.50N-Ff
1.5N=2.50N-Ff
1.5N/2.50N=Ff
Ff=0.6N
m*a=Ft-Ff
2.00kg*0.750=2.50N-Ff
1.5N=2.50N-Ff
1.5N/2.50N=Ff
Ff=0.6N
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