Asked by Anonymous
Prove that log base a of x divided by log base a/b of x is equal to 1+log base a of(1/b)
Where do I start?
Where do I start?
Answers
Answered by
Steve
since
log_u(x)/log_v(x) = log_v(u) and
log_u(x) = 1/log_x(u), we have
log_a/b(a) = 1/log_a(a/b)
= log_a(a) + log_a(1/b)
= 1 + log_a(1/b)
If those two properties of logs have not yet been delivered to you, work to convince yourself that they are true. I'm sure you can find many proofs online.
log_u(x)/log_v(x) = log_v(u) and
log_u(x) = 1/log_x(u), we have
log_a/b(a) = 1/log_a(a/b)
= log_a(a) + log_a(1/b)
= 1 + log_a(1/b)
If those two properties of logs have not yet been delivered to you, work to convince yourself that they are true. I'm sure you can find many proofs online.
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