Asked by Sean

A mass of 0.55 kg attached to a vertical spring stretches the spring 36 cm from its original equilibrium position.
The acceleration of gravity is 9.81 m/s2 . What is the spring constant?
Answer in units of N/m.
Answered by Henry
F = M*g = 0.55kg * 9.8N/kg = 5.39 N.

K = 5.39N./0.36m = 14.97 N/m
There are no AI answers yet. The ability to request AI answers is coming soon!