two points A and B are 562 meter apart on a level stretch of road leading to a hill . the angle of elevation from A is 26degree 30minutes, and angle of elevation from B is 36degee 40minutes. how high is the hill ?

Answer 1

in your sketch mark the top of the mountain as P
and its base as Q
Label AB = 562 and mark you angles
In triangle ABP
angle A = 22° 30'
angle B = 180° - 30° 40 = 149° 20'
angle C = 180 - A-B = 8° 10'

by the Sine Law, you can find BP , which is the hypotenuse of triangle PBQ
it is then easy to find PQ

Note, I left the angles in DMS format, and used the DMS key on my calculator
otherwise change your angles to decimals