Asked by Lena
In an experiment, you dissolve 0.30 g of KHP (MM = 204.22 g/mol) in 20 mL of DI water and titrate the sample with 0.10 M NaOH. Calculate the volume (to the nearest mL) of NaOH required to reach the equivalence point.
IS it a) 3 b)15 c)20 d)30 e)100
I have done MV=MV (0.3/204.22)(20)=(0.10)(V) and have gotten 0.2938 Which is nowhere close to any of these answers. I don't know what I am doing wrong. Please help.
IS it a) 3 b)15 c)20 d)30 e)100
I have done MV=MV (0.3/204.22)(20)=(0.10)(V) and have gotten 0.2938 Which is nowhere close to any of these answers. I don't know what I am doing wrong. Please help.
Answers
Answered by
DrBob222
This is not a dilution problem.
mols KHP = grams/molar mass = ?
mols NaOH = mols KHP
M NaOH = mols NaOH/L NaOH
Solve for L NaOH and convert to mL.
mols KHP = grams/molar mass = ?
mols NaOH = mols KHP
M NaOH = mols NaOH/L NaOH
Solve for L NaOH and convert to mL.
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