Asked by Joe

Solve for x?

xln(x) + 1 > x + ln(x)


e^1/x > 1

Any help would be appreciated. THANK YOU!

Answers

Answered by drwls
(2) e^(1/x) > 1

When e^(1/x) = 1, (taking natural logs of both sides)
(1/x) = 0
x = infinity

Any positive number x that is less than infinity satisfies the inequality.

(1) The solution to
xln(x) + 1 = x + ln(x)
is x = 1. Values x between 0 and satisfy the inequality.

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