Asked by Paige
How fast would a 4.8 kg object slide down a frictionless incline of 10.3 degrees?
Answers
Answered by
Damon
infinitely fast, constant acceleration forever
m a = m * 9.81 * sin 10.3
so
a = g sin 10.3 = 9.81 sin 10.3
so
v = (9.81 sin 10.3) t
v is proportional to time, forever
m a = m * 9.81 * sin 10.3
so
a = g sin 10.3 = 9.81 sin 10.3
so
v = (9.81 sin 10.3) t
v is proportional to time, forever
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