Asked by yeng

a solution of CH4N2O in water has a vapor pressure of 19.6 torr. at 25C. what is the mole fraction of CH4N2O in this solution? HELP ME

WATER PURE PRESSURE (P0) IS 23.8 TORR

VAPOR PRESSURE IS 19.6 TORR
DONT KNOW HOW TO SOLVE IT ?

P(SOLUTION)= X (CH4N2O) WATER (PURE PRESSUR
Answered by yeng
i need help
Answered by DrBob222
psoln = X<sub>H2O</sub>P<sup>o</sup><sub>H2O</sub>
Then XH2O + XCH4N2O = 1.
Solve for XCH4N2O
Answered by yeng
how u find mole fraction please
Answered by yeng
mole fraction of water
Answered by yeng
psoln = XH2OPoH2O
Then XH2O + XCH4N2O = 1.
Solve for XCH4N2O

im confused still
Answered by DrBob222
The first line is the equation you use. You know psoln = 19.6 torr and you know Po H2O is 23.8 torr. Solve for XH2O. It's as simple as 19.6/23.8 = ?
Then convert to XCH4N2O.
Answered by DrBob222
After you have XH2O, then use the next equation,
XH2O + XCH4N2O = 1
0.824 + X = 1
Solve for X.
Answered by yeng
i have another question.
Answered by yeng
oles in 4.9g = grams/molar mass = ?
m = molality = mols/kg solvent
delta T = Kf*m. Solve for delta T and subtract from the normal freezing point of H2O (0C) to find the new freezing point.

pi = MRT
M is molarity but in dilute solutions M and m are almost the same. R is 0.08206 and T must be in kelvin; pi comes out in atmospheres.

for this problem the answer is 1.94 not 2.02 what is wrong?
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