Question
A solution of NH3 in water has a pH of 11.17. Calculate it's molarity
Answers
DrBob222
pH = 11.17 so pOH = 14-11.17
Then pOH = -log(OH^-). Calculate OH^-
..........NH3 + H2O ==> NH4^+ + OH^-
Plug in OH^- (also equal to NH4^+) into Kb expression and solve for NH3.
Then pOH = -log(OH^-). Calculate OH^-
..........NH3 + H2O ==> NH4^+ + OH^-
Plug in OH^- (also equal to NH4^+) into Kb expression and solve for NH3.