Question
points p and q are trisection points on segment ab. if aq= 7x+6 and pq= 3x+5 find all possible values for the length of ab?
Answers
Steve
well, we have
aq = 2(pq), so
7x+6 = 2(3x+5)
x = 4
ab = 3(pq) = 3(17) = 51
aq = 2(pq), so
7x+6 = 2(3x+5)
x = 4
ab = 3(pq) = 3(17) = 51