Asked by jennifer

Five points lie in the same plane with no three points on the same line. A circle can be drawn through any three of the five points. What is the total number of different circle that can be drawn such that each circle passes through three of the five points?

Answers

Answered by Damon
how many combinations of three from 5
n!/[ r!(n-r)! ]
5!/[2!(3!)] = 10

or do one by 1 the hard way

A B - C, D, E --> 3
A C - D, E -->2
A D - E -->1

B C - D, E -->2
B D - E -->1

C D - A -->1

3+2+1+2+1+1 = 10

Answered by Reiny
Since no choice of 3 points forms a straight line, you are simply finding the number of ways to choose 3 of the 5 points, which is
C(5,3) or 5!/(3!2!) = 10
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions