Asked by josh
can you help me to solve each triangle described below using ΔABC :
1)a = 10, A = 16°, B = 49°
2)a = 8, b = 7, A = 88°
1)a = 10, A = 16°, B = 49°
2)a = 8, b = 7, A = 88°
Answers
Answered by
Steve
A+B+C=180°, so C=115°
Now use law of sines:
b/sin49° = c/sin115° = 10/sin16°
#2:
sin88°/8 = sinB/7, so
B = 61° or 109°
But, since A=88°, B cannot be 109°, so there's no ambiguous case here.
Now you know A and B, so you can find C and c as above.
Now use law of sines:
b/sin49° = c/sin115° = 10/sin16°
#2:
sin88°/8 = sinB/7, so
B = 61° or 109°
But, since A=88°, B cannot be 109°, so there's no ambiguous case here.
Now you know A and B, so you can find C and c as above.
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