Ask a New Question

Asked by Anonymous


For each parabola, find the vertex and focus.

x= (1/400)y^2


y= 1/8(x-3)^2-1
10 years ago

Answers

Answered by Steve
well, recall that a parabola with vertex at (h,k) is

y-k = a(x-h)^2

and for the focus, take a peek at

http://www.purplemath.com/modules/parabola.htm
10 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

Find the vertex of the parabola. Sketch the graph. Y=x^2+2x-3 Find a parabola with equation y = ax^2 + bx + c that has slope 6 at x = 1, slope −14 at x = −1, an... Find an equation of a parabola with the vertex at (3, -8) and (5, -2). Find an equation of parabola that has the indicated vertex and whose graph passes through the given... Find the vertex of the parabola y = f(x)= x^2 + 8 x - 11 x coordinate = y coordinate = Grap... Find the equation of a parabola where the vertix is at origin and the parabola opens to the left and... Find the length of the parabola y^2=4ax cut off the line x=a about the x-axis find the equation of parabola with latus rectum joinin.g (2, 5), (2, -3). find the equation of para... Find the equation of a parabola that passes through the points (1,6) (2,20) and (3,40) Find an equation of a parabola satisfying the given information Focus (6,4), directrix x= -7
Submit Your Answer

Question


For each parabola, find the vertex and focus.

x= (1/400)y^2


y= 1/8(x-3)^2-1

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use