Question

Find an equation of parabola that has the indicated vertex and whose graph passes through the given point.
Vertex (-3,5)
Point (-6,1)

Answer 1

****Point(-6,-1)

Answer 2

from the vertex, we know that

y = a(x+3)^2+5
Now plug in the values to get a:

1 = a(-6+3)^2 + 5
9a = -4
a = -4/9

y = -4/9 (x+3)^2 + 5

See

http://www.wolframalpha.com/input/?i=y+%3D+-4%2F9+%28x%2B3%29^2+%2B+5