Asked by Zahra ferdous
A 10 meter long seesaw has a boy of mass 20 kg sitting on one end . How far away from him should a girl of mass 30kg sit to balance the seesaw?
Answers
Answered by
Damon
I am not sure where the fulcrum is but if it is in the middle then:
20 * 5 = 30 * x
x = 5(2/3) = 10/3 from center
which is 10/3 + 5 from the boy
which is
25/3 = 8 1/3 meters from the boy
20 * 5 = 30 * x
x = 5(2/3) = 10/3 from center
which is 10/3 + 5 from the boy
which is
25/3 = 8 1/3 meters from the boy
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