Question

If a ball is thrown directly upward with a velocity of 26 ft/s, its height (in feet) after t seconds is given by y = 26t − 16t^2. What is the maximum height attained by the ball?

-Please just post answer if possible, my calculations are off. Just want to make sure I am correct.

Answer 1

well, you want y when x = -b/2a = 26/32

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