V = omega r = 255 (.320)
382 = (1/2)V t
because distance = average speed time time if a is constant
solve that for t
t = 764 / V
382 = (1/2) a t^2
solve for a, LINEAR aceleration
alpha = angular acceleration = a/r
A dragster starts from rest and accelerates down a track. Each tire has a radius of 0.320 m and rolls without slipping. At a distance of 382 m, the angular speed of the wheels is 255 rad/s. Determine (a) the linear speed of the dragster and (b) the magnitude of the angular acceleration of its wheels.
1 answer
1 answer