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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 24 ft/s. a.)...Asked by Anonymous
A baseball diamond is a square with side 90 ft. a batter hits the ball and runs toward first base with a speed of 24 ft/s.
(a) At what rate is his distance from second base decreasing when he is halfway to first base?
(b) At what rate is his distance from third base increasing at the same moment?
(a) At what rate is his distance from second base decreasing when he is halfway to first base?
(b) At what rate is his distance from third base increasing at the same moment?
Answers
Answered by
bobpursley
draw a triangle vertexs:runner, secondbase, firstbase
a) x= distance to second base frm runner
90 ft = distance second to first
l= distance frm runner to first base
so l^2+90^2=x^2
and given dl/dt=24ft/sec
2l dl/dt+0=2xdx/dt
solve for dx/dt when l=45
you will have to calculalte x.
b. draw the traingle from second to runner to third to second. Set it up the same, same methodology
a) x= distance to second base frm runner
90 ft = distance second to first
l= distance frm runner to first base
so l^2+90^2=x^2
and given dl/dt=24ft/sec
2l dl/dt+0=2xdx/dt
solve for dx/dt when l=45
you will have to calculalte x.
b. draw the traingle from second to runner to third to second. Set it up the same, same methodology