Asked by Yasmin
When calcium chloride and ammonium phosphate are mixed, an insoluble precipitate of calcium phosphate forms and falls out of solution. After careful analysis of the purified precipitate, 8.16 * 10^25 atoms of calcium are found in the solid. How many other atoms are in the purified precipitate? (Note: the precipitate is only calcium phosphate)
Answers
Answered by
DrBob222
The ppt is Ca3(PO4)2.
You have 8.16E25 atom Ca ions.
That's 8.16E25 x (1 mol/6.02E23) = ? mols Ca and divided by 3 = mols Ca3(PO4)2.
From there you know you have twice that mols P atoms (mols P x 6.02E23 = atoms P) and 8x that number of mols O atoms (atoms O = mols O x 6.02E23).
You have 8.16E25 atom Ca ions.
That's 8.16E25 x (1 mol/6.02E23) = ? mols Ca and divided by 3 = mols Ca3(PO4)2.
From there you know you have twice that mols P atoms (mols P x 6.02E23 = atoms P) and 8x that number of mols O atoms (atoms O = mols O x 6.02E23).