Asked by lawyer
Got a problem here. Can someone explain how to write an equation in slope intercept form for the line that passes through the point (4,2) and is perpendicular to the graph y=1/2x+1.
Answers
Answered by
Reiny
since in the form y = mx + b, the slope of the line is m
so for your line y = (1/2)x + 1, the slope is 1/2
But for perpendicuar lines, their slopes are opposite reciprocals of each other, so the slope of your new line must be -2/1 or -2
and the new equation must be
y = -2x + b
with (4,2) lying on it, so
2 = -2(4) + b
10 = b
new equation: y = -2x + 10
so for your line y = (1/2)x + 1, the slope is 1/2
But for perpendicuar lines, their slopes are opposite reciprocals of each other, so the slope of your new line must be -2/1 or -2
and the new equation must be
y = -2x + b
with (4,2) lying on it, so
2 = -2(4) + b
10 = b
new equation: y = -2x + 10
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.