Calculate the freezing and boiling points of a solution containing 14.9g FeCl3 in 176g water.

Answer 1

calculate the moles of Ferric Chloride

molality=molesFeCl3/.176

freezing point= 0 - m*1.86
boiling point= 100+m*0.51

Answer 2

Note: Don't forget the van't Hoff factor of 4 for FeCl3.