Question

2. How many cells connected in series, each having an EMF of 1.5 V
and internal resistance of 0.2 Ω would be required to pass a current of 1.5 A
through a resistance of 40 Ω.

Answer 1

Load current=1.5 amp
load terminal voltage= 40*1.5=60volts.

voltage drop per battery: .2*1.5=.30 volta

60volts=(1.5-.3)n
n= 50 batteries.

Answer 2

yes