Asked by lindsey
if a 175 g stationary hockey puck is struck with a force of 405 N east through a displacement of 245 mm east while in contact with a stick, determine the velocity of the puck as it leaves the stick.
Answers
Answered by
Damon
a = F/m
a = 405/175
vf = a t where vf is final speed at .245 meters and t is acceleration time
average speed = vf/2
.245 = average speed * t
.245 = ( vf/2) t
so
vf t =.49 but vf = a t
so
a t^2 = .49 (same as d = (1/2) a t^2 )
solve for t
then
Vf = a t
a = 405/175
vf = a t where vf is final speed at .245 meters and t is acceleration time
average speed = vf/2
.245 = average speed * t
.245 = ( vf/2) t
so
vf t =.49 but vf = a t
so
a t^2 = .49 (same as d = (1/2) a t^2 )
solve for t
then
Vf = a t
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