Asked by Jake

A cat dozes on a stationary merry-go-round, at a radius of 6.9 m from the center of the ride. The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.3 s. What is the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place?
Answered by bobpursley
centripetal force= friction force
m*w^2 r= mu*mg

w=2PI/period= 2PI/7.3 rad/sec

solve for mu.
Answered by Jake
what is your "m" in your equations stand for?
Answered by lilly
i really wanna know that why is centripetal force equal to frictional force???
n a request...
free body diagram please!!
please...