Question
The number of bacteria in a certain culture increased from 500 to 1000 between 7:00 A.M. and 9:00 A.M. Assuming growth is exponential, the number f(t) of bacteria t hours after 7:00 A.M. is given by f(t) = 500(2)^t/2.
(a) Estimate the number of bacteria in the culture at 8:00 A.M., 10:00 A.M., and 11:00 A.M. (Round your answers to the nearest whole number.)
8:00 A.M. bacteria
10:00 A.M. bacteria
11:00 A.M. bacteria
(a) Estimate the number of bacteria in the culture at 8:00 A.M., 10:00 A.M., and 11:00 A.M. (Round your answers to the nearest whole number.)
8:00 A.M. bacteria
10:00 A.M. bacteria
11:00 A.M. bacteria
Answers
t = 1, t = 3 and t = 4
plug and chug
eg
for t = 1 (which is 8am)
500 * 2^(1/2)
500 * 1.414 = 707
plug and chug
eg
for t = 1 (which is 8am)
500 * 2^(1/2)
500 * 1.414 = 707
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