Ask a New Question

Question

Lines tangent to the curve y-1=2x^2+3x pass through the point A(2,-1). Find the x-coordinate(s) of the point(s) of tangency.

The answer is 2+2^1/2, 2-2^1/2, I just don't know how to get there. Please help! Thank you!
10 years ago

Answers

Related Questions

The tangent to the curve 2y= 2x^2 -5x +4 at the point where x=1 is parallel to the norma... Does any tangent to the curve y=ãx cross the x-axis at x= -1? If so, find an equation for the line... 2. The tangent to the curve y = ex2 drawn at the point (e, ee) intersects the line joining the point... the tangent yo the curve y=x^2 +5x -2 @ the point (1,4)intersect the normal to the same curve @ the... the tangent to the curve y=a/x +bx at (1,3) is parallel to the line whose equation is y=2x+1. find t... a line is tangent to the curve y= (x^2 + 3)/ (x+3)^1/2 at the point where x=1. write the equation... The curve has tangent at the point P(-1,-2) find they gradient of this tangent at point P find the tangent to the curve given by the parametric equations: x=1/t y=sqrt(t)e^(-t) The tangent to the curve y = ax²+ bx at the point where x = 1 has gradient 1 and passes through the... the tangent to the curve y = ax^3 at the point where x = 1 passes through the point( 2 , 8). find th...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use